[leetcode_33]Search in Rotated Sorted Array

给定一个sorted 的array但是需要做个调转：比如： 0 1 2 3 4 5 6 7 8 9 某个调转之后：7 8 9 0 1 2 3 4 5 6
输入target，如果array中存在target返回下标，否则，返回-1。
欧克，傻瓜都能想到o(n)的方法，
有没有更快的？o(logn)?二分？二分查找变形一下就行：

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class Solution {
public:
    int ans;
    void searchStep(int A[],int target,int left,int right) 
    {
        if(left > right)
            return;
        int mid = (left+right)/2;
        if(A[mid] == target)
        {
            ans = mid;
            return;
        }
        else
        {
            if(A[mid] > target)
            {
                if(A[right] > A[left])
                {
                    searchStep(A,target,left,mid-1);
                }
                else
                {
                    searchStep(A,target,left,mid-1);
                    searchStep(A,target,mid+1,right);
                }
            }
            else
            {
                if(A[right] > A[left])
                {
                    searchStep(A,target,mid+1,right);
                }
                else
                {
                    searchStep(A,target,mid+1,right);
                    searchStep(A,target,left,mid-1);
                }
            }
        }
    }
    int search(int A[], int n, int target) 
    {
        int left = 0;
        int right = n-1;
        ans = -1;
        searchStep(A,target,left,right);
        return ans;
    }
};