这个题暴力做的,之前用栈解决直方图最大值的算法最坏情况好像比较高。
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class Solution {
public:
int maximalRectangle(vector<vector<char>> &matrix) {
int max = 0;
int **map = new int*[matrix.size()];
for(int i = 0; i < matrix.size(); i++) {
map[i] = new int[matrix[0].size()];
}
for(int i = 0; i < matrix.size(); i++) {
int height = 0;
for(int j = matrix[0].size() - 1; j >= 0; j--) {
if(matrix[i][j] == '1') map[i][j] = ++height;
else {
height = 0;
map[i][j] = height;
}
}
}
for(int i = 0; i < matrix.size(); i++) {
for(int j = 0; j < matrix[0].size(); j++) {
int width = map[i][j];
max = Max(max, width);
for(int k = i + 1; k < matrix.size(); k++) {
if(map[k][j] == 0) break;
else {
width = Min(width, map[k][j]);
max = Max(max, width * (k - i + 1));
}
}
}
}
return max;
}
private:
int Max(int a, int b) {
return a > b ? a : b;
}
int Min(int a, int b) {
return a < b ? a : b;
}
};
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